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e (2.718...) and (3.1415...) pi
Here are some reasons and a conjecture.
![]() As given before, pi is initially 3 in terms of quanta and "degenerates" to 3.14159... as a limit as the quanta become increasingly smaller (width of measuring string included).
But what about "e" ? Is it a degenerate number like pi ? If so, in what way ? I conjecture that "e" degenerates from "2" in the probablility of the appearance of a new particle in any given unit space. Recall that the probability was given as 1/2 (a new particle is either there or it is not). This applied to a standard Euclidean manifold. However, this standard Cartesian three space may be modified by Planck's constant which would allow for variations in length, mass and time such as to maintain a constant 1/R value (where R is the present radius of the universe). Now, clearly the hypothetical "unit cube" of the Euclidean manifold might shrink to the limit of 0 or it might expand without limit.
I propose then that the unit cube is "stretched" greater than 1 unit while others are correspondingly compressed (inverse fractions) and that therefore the probability of finding a new particle in a hypothetical unit cube (unstretched) is less than 1/2. Of course, if one unit cube is compressed and another expanded and the sum of the two is still 2 units ... then the probability is still 1/2. But this situation would not be a case of inverse fractional alteration. Thus, if one unit compresses to 1/3, the other must expand to 3 times yielding a net increase of 1+1/3 unit cubes ... and therefore a corresponding decrease in the probability of finding a new particle since 2 unit cubes now occupy the space of 3+1/3.
![]() Specifically, I conjecture that it is 1/e. And that the further one removes oneself from the beginning of time, the more closely the probability approaches 1/e. If this is so, pi is married to e at the very core of existence.
I have no proof of this but if one should occur to me,
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